Q. $F_{2}$ is formed by reacting $K_{2}MnF_{6}$ with
A) $MnF_{4}$
B) $SbF_{5}$
C) $KSbF_{6}$
D) $MnF_{3}$
Explanation
(b)
$K_{2}MnF_{6} + 2{SbF}_{5} \rightarrow 2{KSbF}_{6} + {MnF}_{3} + \frac{1}{2}F_{2}$
In this reaction, the stronger Lewis acid $SbF_{6}$ displaces the weaker one, $MnF_{4}$ from its salt. $MnF_{4}$ is unstable and readily decomposes to give $MnF_{3}$ and fluorine
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.