Q. The ‘spin –only’ magnetic moment [in units of Bohr magneton, ($\mu_{\beta}$) ]of ${Ni}^{2 +}$ in aqueous solution would be (Atomic number of Ni=28)
A) 2.84
B) 4.90
C) 0
D) 1.73
Explanation
(a)
${Ni}^{2 +}$=[Ar]3$d^{8}$
[table] ⥮ | ⥮ | ⥮ | $\upharpoonleft$ | $\upharpoonleft$ [/table]
Number of unpaired electrons=2
Hence, magnetic moment=$\sqrt{n(n + 2)}$
=$\sqrt{8}$=2.84
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.