(d)
$Sc^{3 +}\ \left( 3d^{0} \right),\ Ti^{4 +}(3d^{0})$ are diamagnetic due to absence of unpaired electrons. While $Pd^{2 +}\left( 4d^{8} \right),\ Cu^{2 +}(3d^{9})$ contain two, and one unpaired electron respectively. Hence, these are paramagnetic