Q. The magnetic moment of a transition metal ion is $\sqrt{15\ }$BM. Therefore, the number of unpaired electrons present in it, is
A) 3
B) 4
C) 1
D) 2
Explanation
(a)
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mu = \sqrt{n(n + 2)}$
$\Rightarrow$ $\sqrt{15} = \sqrt{n(n + 2)}$
$\therefore$ $\ \ n$ =3
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.