Q. Which of the following ions has a magnetic moment of 5.93 BM? (At. no. V=23, Cr=24, Mn=25, Fe=26)
A) ${Mn}^{2 +}$
B) ${Fe}^{2 +}$
C) ${Cr}^{2 +}$
D) $V^{3 +}$
Explanation
(a)
Magnetic moment =$\sqrt{n(n + 2)}\ BM$
Where, $n$ =number of unpaired electrons
5.93=$\sqrt{n(n + 2)}\$
$n$ =5
${Mn}^{2 +}$ ion (3$d^{5}$) has 5 unpaired electrons and magnetic moment is 5.93 BM.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.