(c)
${VOSO}_{4}$ is paramagnetic as well as coloured compound.
The oxidation state of vanadium in ${VOSO}_{4}$ is +4.
V [Z=23]=[Ar]$3d^{3}\ 4s^{2}$
$V^{4 +}$[Z=23]=[Ar] $3d^{1}\ 4s^{0}$
It has one unpaired electron hence, it is paramagnetic in nature.