Q. When calomel reacts with ${NH}_{4}OH$ solution, the compound formed is
A) ${NH}_{2}—Hg—\ Cl$
B) ${Hg}_{2}{Cl}_{2}{NH}_{3}$
C) $Hg\left( {NH}_{3} \right)_{2}{Cl}_{2}$
D) ${HgCl}_{2}{NH}_{3}$
Explanation
(a)
${HgCl}_{2} + 2{NH}_{3}\ \overset{H_{2}O}{\rightarrow}Hg + {NH}_{2}HgCl + {NH}_{4}Cl$
mercuric
amino chloride
$\therefore HgCl_{2}\$on reaction with$\ NH_{4}OH\ \left( or\ NH_{3} + \ H_{2}O \right)\$forms mercuric amino chloride.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.