Q. The oxidation number of Mn in the product of alkaline oxidative fusion of ${MnO}_{2}$ is
A) 2
B) 3
C) 4
D) 6
Explanation
(d)
$2{MnO}_{2} + 4\ KOH + O_{2}$
$\overset{Fusion}{\rightarrow}2K_{2}{MnO}_{4} + 2H_{2}O$
Oxidation number of Mn in $K_{2}MnO_{4}$ is
$2 \times (1) + x + 4( - 2) = 0$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x\ = + 6$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.