(d)
$\left\lbrack Cr\left( {NH}_{3} \right)_{5}\ {NO}_{2} \right\rbrack{Cl}_{2}$ compound shows linkage isomerism because it has $NO_{2}$ group which is ambidentate ligand.
It can be linked via N atom $(—NO_{2})$ or via O atom (—ONO) to form two different isomers.