Q. In an octahedral structure, the pair of d-orbitals involved in $d^{2}\ sp^{3}$ hybridisation is
A) $d_{x^{2} - y^{2}},d_{z^{2}}$
B) $d_{xz}\ ,d_{x^{2} - y^{2}}$
C) $d_{z^{2}},d_{xz}$
D) $d_{xy},d_{yz}$
Explanation
(a)
In the formation of $d^{2}sp^{3}$ hybrid orbitals, two ($n -$1)$d$ orbitals of $e_{g}$ set i.e., $(n - 1)\ d_{z^{2}}and\ (n - 1)d_{x^{2} - y^{2}}$orbitals, one $ns\ and\ three\ np\left( np_{x},\ np_{y}\ and\ np_{z} \right)$ orbitals combine together and form six $d^{2}sp^{3}$ hybrid orbitals.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.