Q. Mixture $X = 0.02$ mole of $\lbrack Co\left( NH_{3} \right)_{5}SO_{4}\rbrack$Br and 0.02 mole of $\left\lbrack Co\left( NH_{3} \right)_{5}Br \right\rbrack SO_{4}$ was prepared in 2 L of solution 1 L of mixture $X +$ excess Ag$NO_{3} \longrightarrow Y$ 1 L of mixture $X +$ excess B$aCl_{2} \longrightarrow Z$ Number of moles of $Y$ and $Z$ are
A) 0.01, 0.01
B) 0.01,0.02
C) 0.02, 0.01
D) 0.02, 0.02
Explanation
(a)
$\left\lbrack Co\left( NH_{3} \right)_{5}SO_{4} \right\rbrack Br + AgNO_{3} \longrightarrow \left\lbrack Co\left( NH_{3} \right)_{5} \bullet SO_{4} \right\rbrack + A$gBr
_{0.02mol (Y)}
$\left\lbrack Co\left( NH_{3} \right)_{5}Br \right\rbrack{SO}_{4} + {BaCl}_{2} \longrightarrow \left\lbrack Co\left( NH_{3} \right)_{5}\ Br \right\rbrack{Cl}_{2} + {BaSO}_{4}$
_{0.02mol (Z)}
On using one liter solution we will get 0.01 mole $Y$ and 0.01 mole $Z$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.