Given the molecular formula of the hexa coordinated complexes is (A) ${CoCl}_{3}\ .6{NH}_{3}$ (B) ${CoCl}_{3}\ .5{NH}_{3}$ (C) ${CoCl}_{3}\ .4{NH}_{3}$ If the number of coordinated ${NH}_{3}$molecules in A, B and C respectively are 6, 5 and 4 the primary valency in (A),(B) and (C) are

Question

Dr. Abubacker · Accepted Answer

(b)
The primary valency is ionizable valency. It corresponds to oxidation state of metal. The primary valency is always satisfied by anion.
$\left\lbrack Co\left( {NH}_{3} ight)_{6} ightbrack{Cl}_{3}\  \longrightarrow \lbrack Co\left( {NH}_{3} ight)_{6}brack + 3{Cl}^{-}$
(A)
$	herefore$ Number of primary valency is 3
$\lbrack Co\left( {NH}_{3} ight)_{5}Clbrack Cl2\  \longrightarrow \lbrack Co\left( {NH}_{3} ight)_{5}Clbrack + 2{Cl}^{-}$
(B)
$	herefore$ Number of primary valency is 2
$\lbrack Co\left( {NH}_{3} ight)_{4}{Cl}_{2}brack Cl\  \longrightarrow \lbrack Co\left( {NH}_{3} ight)_{4}brack + {Cl}^{-}$
$	herefore$ Number of primary valency is 1.

Q. Given the molecular formula of the hexa coordinated complexes is (A) ${CoCl}_{3}\ .6{NH}_{3}$ (B) ${CoCl}_{3}\ .5{NH}_{3}$ (C) ${CoCl}_{3}\ .4{NH}_{3}$ If the number of coordinated ${NH}_{3}$molecules in A, B and C respectively are 6, 5 and 4 the primary valency in (A),(B) and (C) are

Explanation

Reviewed by Dr. Abubacker

Want more practice?