Q. The effective atomic number of Cr (At. No.=24)in $\left\lbrack Cr\left( {NH}_{3} \right)_{6} \right\rbrack{Cl}_{3}\$is
A) 35
B) 27
C) 33
D) 36
Explanation
(c)
Effective atomic number =electrons in ${Cr}^{3 +}$ +electrons form 6NH_{3} ligands.
=21+6$\times$2=33
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.