Q. The reaction, $\left\lbrack Fe(CNS)_{6} \right\rbrack^{3 -}\ \longrightarrow \left\lbrack {FeF}_{6} \right\rbrack^{3 -}$ taken place with

A) Decrease in magnetic moment
B) Increase in magnetic moment
C) Decrease in coordination number
D) Increase in coordination number
Explanation

(b)
$F^{-}$ is a weak field ligand and $\left\lbrack FeF_{6} \right\rbrack^{3 -}$ is an outer-orbital complex
[image:9_image167.emf]
$\left\lbrack FeF_{6} \right\rbrack^{3 -}$ shows $sp^{3}\ d^{2}$ hybridisation and $Fe^{3 +}$ has five unpaired electrons.
In $\left\lbrack Fe(CNS)_{6} \right\rbrack^{3 -},\ CNS^{-}$ is a strong field ligand and is inner orbital complex.
$\left\lbrack Fe(CNS)_{6} \right\rbrack^{3 -}$
[image:9_image168.emf]
$\left\lbrack Fe(CNS)_{6} \right\rbrack^{3 -}$ shows $d^{2}\ sp^{3}$ hybridisation and has one unpaired electron.
Hence, the reaction.
$\left\lbrack Fe(CNS)_{6} \right\rbrack^{3 -} \rightarrow \left\lbrack FeF_{6} \right\rbrack^{3 -}$
takes place with increase in magnetic moment.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.