Q. Hybridization of Fe in $\left\lbrack K_{3}Fe(CN)_{6} \right\rbrack\$is
A) $sp^{3}$
B) $d^{2}sp^{3}$
C) $sp^{3}d^{2}$
D) $dsp^{3}$
Explanation
(b)
$K_{3}\lbrack Fe(CN)_{6}\rbrack$
Electronic configuration of $Fe = \lbrack Ar\rbrack 3d^{6}4s^{2}$
Electronic configuration of $Fe^{3 +} = \lbrack Ar\rbrack 3d^{5}$
Number of ligand (Coordination number)=6
Nature of ligand in strong field
[image:9_image170.emf]
Hybridisation of $Fe$ is $d^{2}sp^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.