Q. The oxidation state of Fe in the brown ring complex $\left\lbrack Fe\left( H_{2}O \right)_{5}NO \right\rbrack{SO}_{4}$is
A) +3
B) 0
C) +2
D) +1
Explanation
(d)
Let the oxidation state of Fe in $\left\lbrack Fe\left( H_{2}O \right)_{5}NO \right\rbrack{SO}_{4}\$is x.
$\left\lbrack Fe\left( H_{2}O \right)_{5}NO \right\rbrack^{2 +}$
⇒ x+0+1=2
$\therefore$ x =+1
Here, NO exists as nitrosyl ion (${NO}^{+}$).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.