Q. The correct statement with respect to the complexes $Ni(CO)_{4}\ and\ \left\lbrack Ni\ (CN)_{4} \right\rbrack^{2 -}$ is
A) Nickel is in the same oxidation state in both
B) Both have terahedral geometry
C) Both have square planar geometry
D) Have tetrahedral and square planar geometry respectively
Explanation
(d)
In $Ni(CO)_{4}$, Ni is in zero oxidation state. It has tetrahedral geometry but is diamagnetic. In $\left\lbrack Ni\ (CN)_{4} \right\rbrack^{2 -}$ , Ni is in +2 oxidation state. It is $dsp^{2}$ hybridised and have square planar shape. The compound is diamagnetic.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.