(a)
Number of moles of pentaaqua chloro chromium III chloride in the solution.
$n = \frac{0.01 \times 100}{1000}$=0.001
1 mole of $\left\lbrack Cr\left( H_{2}O \right)_{5}Cl \right\rbrack{Cl}_{2}\$gives 2 moles of chloride ions.
Moles of chloride ions =0.001 $\times$2=0.002
Mass of AgCl produced =0.002 $\times$143.5
=287.0$\times 10^{- 3}g$