Q. Maximum number of open chain isomers that an alkene can have with the molecular formula $C_{4}H_{8}$ is
A) 5
B) 4
C) 3
D) 2
Explanation
(a)
The following isomers the alkene have
(i) $CH_{3} - CH_{2} - CH = CH_{2}$
(ii) $CH_{3} - CH = CH - CH_{3}$
[image:9_image176.emf]
$CH_{3}$
$|$
(v) $CH_{3} - C = {CH}_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.