Q. Which class of compounds can exhibit geometrical isomerism?
A) $C_{6}H_{5}CH = NOH$
B) $CH_{3}CH = CHCH_{3}$
C) [image:9_image59.emf]
D) All of the above
Explanation
(d)
All the compounds in which there should be restricted rotation about a bond in the molecule, show geometrical isomerism. Oximes of the type $CH_{3} - CH = N - OH$, $C_{6}H_{5} - CH = N - OH$, $C_{6}H_{5} - C = N - OH$ and cyclic
$|$
$CH_{3}$
Compound like [image:9_image180.emf] show geometrical isomerism
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.