Q. The oxidation state of Cr in $\left\lbrack Cr\left( {NH}_{3} \right)_{4}\ {Cl}_{2} \right\rbrack^{+}$ is
A) 0
B) +1
C) +2
D) +3
Explanation
(d)
$\left\lbrack Cr\left( {NH}_{3} \right)_{4}{Cl}_{2} \right\rbrack^{+}$
Let oxidation state of Cr =x
NH_{3}=0
Cl=$-$1
Net charge =+1
$\therefore\left\lbrack Cr\left( {NH}_{3} \right)_{4}{Cl}_{2} \right\rbrack^{+}$
x +4$\times$0+2($-$1)=+1
$\therefore$ x =+3
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.