Q.
Number of geometrical isomers for the molecule
A) 2
B) 3
C) 6
D) 5
Explanation
(b)
When $n =$even number then for two identical ends, number of geometrical isomers
$= 2^{n - 1} + 2^{n/2 - 1}$
$= 2^{1} + 2^{0}$
$= 3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.