Q. Geometrical shapes of the complexes formed by the reaction of ${Ni}^{2 +}\ with\ Cl^{-},CN^{-}\ and\ H_{2}O$ , respectively, are

A) Octahedral, tetrahedral and square planar
B) Tetrahedral ,square planar and octahedral
C) Square planar ,tetrahedral and octahedral
D) Octahedral , square planar and octahedral
Explanation

(b)
$Ni^{2 +} + 4CN^{-} \rightarrow \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$
Here $Ni^{2 +}$ has $d^{8}$-configuration with $CN^{-}$ as strong ligand.
[image:9_image205.emf]
$d^{8}$-configuration in strong ligand field gives $dsp^{2}$ hybridisation, hence square planar geometry.
$Ni^{2 +} + 4Cl^{-} \rightarrow \left\lbrack NiCl_{4} \right\rbrack^{2 -}$
Here $Ni^{2 +}$ has $d^{8}$-configuration with $CN^{-}$ as weak ligand.
[image:9_image206.emf]
$d^{8}$-configuration in weak ligand field gives $sp^{3}$hybridisation, hence tetrahedral geometry.
$Ni^{2 +}$ with $H_{2}O$ forms $\left\lbrack Ni\left( H_{2}O \right)_{6} \right\rbrack^{2 +}\$complex and $H_{2}O$ is a weak ligand.
3d
[table] ⥮ | ⥮ | ⥮ | $\upharpoonleft$ | $\upharpoonleft$ [/table]
[image:9_image207.emf]
Therefore, $\left\lbrack Ni\left( H_{2}O \right)_{6} \right\rbrack^{2 +}$has octahedral geometry.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.