Q. Keto form is more stable in
A) $CH_{3}COCH_{2}COOC_{2}H_{5}$
B) $CH_{3}COCH_{2}COCH_{3}$
C) $CH_{3}COCH_{3}$
D) $CH_{3}COCH_{2}COC_{2}H_{5}$
Explanation
(c)
$C = O$ double bond of a carbonyl group is a stronger bond ($> C = O,364\ kJ/mol$) than the $C = C$ bond strength 250 kJ/mol) of the enol. Thus, $CH_{3}COCH_{3}$ is more stable
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.