Q. The ionisation isomer of $\lbrack Cr\left( H_{2}O \right)_{4}Cl({NO}_{2})C\rbrack$ is
A) $\left\lbrack Cr\left( H_{2}O \right)_{4}\left( O_{2}N \right) \right\rbrack{Cl}_{2}$
B) $\lbrack Cr\left( H_{2}O \right)_{4}{Cl}_{2}\rbrack({NO}_{2})$
C) $\lbrack Cr\left( H_{2}O \right)_{4}Cl\ (ONO)\rbrack\ Cl$
D) $\left\lbrack Cr\left( H_{2}O \right)_{4}{Cl}_{2}\left( {NO}_{2} \right) \right\rbrack.H_{2}O$
Explanation
(b)
The ionisation isomer of
[Cr$\left( H_{2}O \right)_{4}Cl\ ({NO}_{2})\rbrack Cl$ is $\lbrack Cr\left( H_{2}O \right)_{4}{Cl}_{2}\rbrack({NO}_{2})$ because of exchanging of ligand and counter ions.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.