Q. Which kind of isomerism is exhibited by octahedral $Co\left( {NH}_{3} \right)_{4}{Br}_{2}Cl$ ?

A) Geometrical and ionisation
B) Geometrical and optical
C) Optical and ionisation
D) Geometrical only
Explanation

(a)
Octahedral $Co\left( {NH}_{3} \right)_{4}{Br}_{2}Cl$ shows ionisation and geometrical isomerism.
In ionisation isomerism ligands show different coordination sphere and the anions present outside the coordination sphere.
These are exchanged with each other as follows
$Co\left( {NH}_{3} \right)_{4}{Br}_{2}Cl$ $\rightleftharpoons \ \ \ \ \left\lbrack Co\left( {NH}_{3} \right)_{4}{Br}_{2} \right\rbrack^{+} + {Cl}^{-}$
I
$\lbrack Co\left( {NH}_{3} \right)_{4}BrCl\rbrack Br\ \rightleftharpoons \left\lbrack Co\left( {NH}_{3} \right)_{4}Br\ Cl \right\rbrack^{+} + {Br}^{-}$
II
In geometrical isomerism, coordination number of central atom (cobalt) is six and shape is octahedral, so it shows following geometrical isomers.
[image:9_image226.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.