Q. Amongst $Ni(CO)_{4},\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}\$and$\ \left\lbrack NiCl_{4} \right\rbrack^{2 -}$
A) $Ni(CO)_{4}$ is diamagnetic,$\left\lbrack NiCl_{4} \right\rbrack^{2 -}$ and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are paramagnetic
B) $Ni(CO)_{4}\$and$\ \left\lbrack NiCl_{4} \right\rbrack^{2 -}$ are diamagnetic and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$is paramagnetic
C) $Ni(CO)_{4}\$and$\ \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are diamagnetic and $\left\lbrack NiCl_{4} \right\rbrack^{2 -}$ is paramagnetic
D) $\left\lbrack NiCl_{4} \right\rbrack^{2 -}$and$\ \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are diamagnetic and $Ni(CO)_{4}$ is paramagnetic
Explanation
(c)
The electronic configuration of $Ni\$in${\ \left\lbrack Ni(CN)_{4} \right\rbrack}^{2 -},\left\lbrack NiCl_{4} \right\rbrack^{2 -}\$and$\ Ni(CO)_{4}$ are as following
$Ni\$in$\ \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$
[image:9_image241.emf]
$Ni^{2 +}$ in $\left\lbrack NiCl_{4} \right\rbrack^{2 -}$
[image:9_image242.emf]
Ni in $\lbrack Ni(CO)_{4}\rbrack$
[image:9_image243.emf]
CO and $CN^{-}\$are strong ligands so, they induces pairing of electrons so, their complexes are diamagnetic which, $Cl^{-}\$is a weak ligand so, it does not induce the pairing of electrons so, its complex is paramagnetic
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.