Q. The oxidation number of Fe in brown ring $\left\lbrack Fe\left( H_{2}O \right)_{5}NO \right\rbrack^{2 +}$ is
A) 0
B) +1
C) +2
D) +3
Explanation
(b)
NO is in ${NO}^{+}$form.
Let the oxidation state of Fe is x
x +0⨯5+(+1)=+2
x =2$-$1
x =+1
Hence, the oxidation number of Fe in brown ring $\left\lbrack Fe\left( H_{2}O \right)_{5}NO \right\rbrack^{2 +}$ is +1.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.