Q. Which of the following pairs represents linkage isomers?
A) $\lbrack Cu\left( {NH}_{3} \right)_{4}\rbrack\lbrack{PtCl}_{4}\rbrack\ and\ \lbrack Pt\ \left( {NH}_{3} \right)_{4}\rbrack\lbrack{CuCl}_{4}\rbrack$
B) $\left\lbrack Pd\left( {PPh}_{3} \right)_{2}\ (NCS)_{2} \right\rbrack\ and\ \lbrack Pd\left( {PPh}_{3} \right)_{2}\ (SCN)_{2}\rbrack\ \$
C) $\left\lbrack Co\left( {NH}_{3} \right)_{5} \right\rbrack{NO}_{3}{SO}_{4}\ and\ \left\lbrack Co\left( {NH}_{3} \right)_{5}{SO}_{4} \right\rbrack{NO}_{3}$
D) $\left\lbrack {PtCl}_{2}\left( {NH}_{3} \right)_{4}\rbrack{Br}_{2}\ and\ {\lbrack PtBr}_{2}\left( {NH}_{3} \right)_{4} \right\rbrack{Cl}_{2}\$
Explanation
(b)
Linkage isomerism is caused due to presence of ambidentate ligands. $\left\lbrack Pd\left( {PPh}_{3} \right)_{2}(NCS)_{2} \right\rbrack and\ \lbrack Pd\left( {PPh}_{3} \right)_{2}\ (SCN)_{2}\rbrack\$are linkage isomers due to SCN, ambidentate ligand.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.