Q. Which one of the following has an optical isomer? (en=ethylenediamine)
A) $\left\lbrack Zn(en)\left( {NH}_{3} \right)_{2} \right\rbrack^{2 +}$
B) $\left\lbrack Co(en)_{3} \right\rbrack^{3 +}$
C) $\left\lbrack CO\left( H_{2}O \right)_{4}(en) \right\rbrack^{3 +}$
D) $\left\lbrack Zn(en)_{2} \right\rbrack^{2 +}$
Explanation
(b)
Complex $\left\lbrack Co(en)_{3} \right\rbrack^{3 +}\$has no plane of symmetry and centre of symmetry that’s why it is optically active.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.