Q. The coordination number and oxidation number of X in the following compound $\lbrack X\left( {SO}_{4} \right)\left( {NH}_{3} \right)_{5}\rbrack Cl\$will be
A) 10 and 3
B) 2 and 6
C) 6 and 3
D) 6 and 4
Explanation
(c)
Coordination number is the number of ligand $\sigma$-bonded to metal-atom. Hence, coordination number of X in $\lbrack X\left( {SO}_{4} \right)\left( {NH}_{3} \right)_{5}\rbrack Cl$ is 6. Let oxidation state of X in the complex be ‘y’ then
y +($-$2)+5(0)+($\ -$1)=0
y $-$2$-$1=0
y =+3
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.