Q. The coordination number and oxidation state of Cr in $K_{3}\lbrack Cr\left( C_{2}O_{4} \right)_{3}\rbrack$ are respectively
A) $+ 6$ and +3
B) 3 and 0
C) 4 and +2
D) 3 and +3
Explanation
(a)
Its coordination number will be 6 because it is bonded with three bidentate ligands
$x + 3( - 2) + 3( + 1) = 0 \Rightarrow x = + 3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.