Explanation

(d)
Cl, being a weak field ligand, does not cause pairing of d-electrons of the metal atom and thus, forms outer orbital complex as.
In $\left\lbrack Fe(Cl)_{6} \right\rbrack^{3 -},\ Fe$ is present as $Fe^{3 +}$
$Fe^{3 +} = \lbrack Ar\rbrack 3d^{5}\ 4s^{0}\ 4p^{0}$
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$\left\lbrack Fe(Cl)_{6} \right\rbrack^{3 -} = \lbrack Ar\rbrack$
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