(a)
For $K_{4}\lbrack Fe(CN)_{6}\rbrack$, the EAN of ${Fe}^{2 +}$ ion =(26$-$2+12) =36 .
Hence it follows EAN rule, as its EAN is equal to number of electrons of Kr (inert gas), i.e., 36.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.