(d)
$\left\lbrack Pt\left( {NH}_{3} \right)_{6}\ \right\rbrack{Cl}_{4}\$complex gives five ions in the solution.
$\left\lbrack Pt\left( {NH}_{3} \right)_{6}\ \right\rbrack{Cl}_{4}\ \rightleftharpoons \left\lbrack Pt\left( {NH}_{3} \right)_{6}\ \right\rbrack^{4 +} + 4{Cl}^{-}$