Q. In the coordination compound, $K_{4}\lbrack Ni(CN)_{4}\rbrack$, the oxidation state of nickel is
A) -1
B) 0
C) +1
D) +2
Explanation
(b)
$K_{4}\lbrack Ni(CN)_{4}\rbrack \longrightarrow 4K^{+} + \ \left\lbrack Ni(CN)_{4} \right\rbrack^{4 -}$
x +(4$\times -$1)=$\ -$4
x $-$ 4=$-$4
x =0
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.