Q. $CH_{3}$ $|$ $\left( CH_{3} \right)_{2}CHCHOH\ \ \underset{–H_{2}O\ \ }{\overset{\ \ Acid\ \ \ \ }{\rightarrow}}\ X$ The major product obtained in this reaction is
A) $\left( CH_{3} \right)_{2}CHCH = CH_{2}$
B) $\left( CH_{3} \right)_{2}C = CH - CH_{3}$
C) 1 : 1 mixture of (a) and (b)
D) None of the above
Explanation
(b)
Many a time unexpected products result during dehydration of alcohols.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.