Q. $CH_{3}CH_{2}OH$ convert into $CH_{3}CHO$ in the presence of
A) $Na_{2}Cr_{2}O_{7}$ and NaOH
B) $Na_{2}Cr_{2}O_{7}and\ dil.\ H_{2}SO_{4}$
C) NaOH
D) Fe in presence of NaOH
Explanation
(b)
$1{^\circ}$alcohol are converted into aldehyde by reaction with $Na_{2}Cr_{2}O_{7}$ and $H_{2}SO_{4}$.
$CH_{3}CH_{2}OH + \lbrack O\rbrack\overset{Na_{2}Cr_{2}O_{7} + H_{2}SO_{4}}{\rightarrow}CH_{3}CHO + H_{2}O$
ethyl alcohol ethanal
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.