Q. $C_{6}H_{5} - CH = CHCHO\overset{\ \ \ \ \ X\ \ \ \ }{\rightarrow}C_{6}H_{5}CH = CHCH_{2}OH$ In the above sequence X can be
A) $H_{2}/Ni$
B) $NaBH_{4}$
C) $K_{2}Cr_{2}O_{7}/H^{+}$
D) Both (a) and (b)
Explanation
(b)
$NaBH_{4}$ and $LiAlH_{4}$ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.
$C_{6}H_{5} - CH = CHCHO\overset{\ \ NaBH_{4}\ \ \ }{\rightarrow}C_{6}H_{5} - CH = CH.CH_{2}OH$
cinnamic aldehyde cinnamic alcohol
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.