Q. The order of reactivity of the following alcohols

A) $I > II > III > IV$
B) $I > III > II > IV$
C) $IV > III > II > I$
D) $IV > III > I > II$
Explanation

(c)
The order of reactivity depends upon the stability of the carbocation formed $ie,\ FCH_{2}\begin{matrix}
+ \\
C
\end{matrix}HCH_{3},\ FCH_{2}CH_{2}\begin{matrix}
+ \\
C
\end{matrix}HCH_{3},\ CH_{3}\begin{matrix}
+ \\
C
\end{matrix}HCH_{3}$ and$\ Ph\begin{matrix}
+ \\
C
\end{matrix}H_{2}$. The stability order of carbocations is $Ph\begin{matrix}
+ \\
C
\end{matrix}H_{2} > CH_{3}\begin{matrix}
+ \\
C
\end{matrix}HCH_{3} > FCH_{2}{CH}_{2}\begin{matrix}
+ \\
C
\end{matrix}HCH_{3} > FCH_{2}\begin{matrix}
+ \\
C
\end{matrix}HCH_{3}$. Thus, the order of reactivity follows the order IV > III > II> I

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.