Q. $CH_{3}CH_{3}$ $|$ $|$ In the reaction $Ph - C - C - Ph\ \overset{\ \ \ Conc.\ H_{2}SO_{4}\ \ \ }{\rightarrow}\ A$ The product $A$ is $|$ $|$ OH $OH$
A) $CH_{3}\ \ CH_{3}$
$|\$ $|$
$Ph - C = C - Ph$
B) [image:11_image81.emf]
C) $\ \ \ \ CH_{3}\ O$
$|$ $\ ||$
$Ph - C - C - CH_{3}$
$|$
Ph
D) $CH_{3}O$
$|$ $||$
$Ph - C - C - Ph$
$|$
$CH_{3}$
Explanation
The correct answer is Option C: $\ \ \ \ CH_{3}\ O$ $|$ $\ ||$ $Ph - C - C - CH_{3}$ $|$ Ph.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.