Q. By which of the following procedures can ethyl $n$-propyl ether be obtained?
A) $C_{2}H_{5}OH\ \overset{HBr\ }{\rightarrow}\ I\ \underset{ether}{\overset{\ \ \ Mg\ \ \ \ \ }{\rightarrow}}\ II\ \overset{H_{2}O\ }{\rightarrow}III\ \underset{CH_{3}CH_{2}Br}{\overset{\ \ \ \ \ \ \ \ Na\ \ \ \ \ \ \ \ \ \ \ }{\rightarrow}}$
B) $C_{2}H_{5}OH\ \overset{HBr\ }{\rightarrow}\ I\ \underset{ether}{\overset{\ \ \ Mg\ \ \ \ \ }{\rightarrow}}\ II\ \underset{2.\ \ H_{3}^{+}O}{\overset{\ \ 1.\ \ {CH}_{2}O\ \ }{\rightarrow}}III\ \underset{CH_{3}CH_{2}Br}{\overset{\ \ \ \ \ \ \ \ Na\ \ \ \ \ \ \ \ \ \ \ }{\rightarrow}}$
C) $C_{2}H_{5}OH + H_{2}SO_{4}\overset{\ 140℃\ }{\rightarrow}$
D) $C_{2}H_{5}OH + Conc.\ H_{2}SO_{4}\overset{\ 180℃\ }{\rightarrow}\ I\ \overset{\ CH_{3}CH_{2}{CH}_{2}Br\ \ }{\rightarrow}$
Explanation
The correct answer is Option B: $C_{2}H_{5}OH\ \overset{HBr\ }{\rightarrow}\ I\ \underset{ether}{\overset{\ \ \ Mg\ \ \ \ \ }{\rightarrow}}\ II\ \underset{2.\ \ H_{3}^{+}O}{\overset{\ \ 1.\ \ {CH}_{2}O\ \ }{\rightarrow}}III\ \underset{CH_{3}CH_{2}Br}{\overset{\ \ \ \ \ \ \ \ Na\ \ \ \ \ \ \ \ \ \ \ }{\rightarrow}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.