(d)
Alcohols ($- OH$) react with sodium and carbonyl compounds [image:11_image271.emf] give precipitate with semicarbazide.
Since, the compound with molecular formula, $C_{3}H_{6}O$ does not give precipitate with simicarbazide and does react with sodium, it is neither a carbonyl compound nor an alcohol. Hence, it must be an ether, i.e., $CH_{2} = CHOCH_{3}$