Q. $CH_{3}CH_{2}OH\underset{step - 1}{\overset{{\ \ \ \ \ \ Cl}_{2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}}CH_{3}CHO\underset{step - 2}{\overset{\ \ \ \ \ 3{Cl}_{2}\ \ \ \ \ }{\rightarrow}}Cl_{3}CCHO$ In above reactions the role of $Cl_{2}$ in step-1 and step-2 respectively is
A) Oxidation, chlorination
B) Reduction, chlorination
C) Oxidation, addition
D) Reduction, substitution
Explanation
(a)
$CH_{3}CH_{2}OH\underset{Step\ 1}{\overset{{\ \ \ \ Cl}_{2}\ \ \ \ \ \ \ \ }{\rightarrow}}CH_{3}CHO$
The above reaction is an example of oxidation. Due to oxidation $–CH_{2}OH$ group is oxidised to $–CHO$ group.
$CH_{3}CHO\underset{Step\ 2}{\overset{\ \ \ 3{Cl}_{2}\ \ \ \ \ }{\rightarrow}}Cl_{3}.C.CHO$
In the second step chlorination takes place. In chlorination hydrogen atom changes by chlorine.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.