(d)
$Br_{2}$ is formed by a redox reaction :
$5Br^{-} + BrO_{3}^{-} + 6H^{+} \rightarrow 3Br_{2} + 3H_{2}O$
-OH group is the activating group and there is $S_{E}$ at o-and p-positions giving yellowish white precipitate of 2, 4, 6-tribromophenol :
[image:11_image300.emf]