Q. What amount of bromine will be required to convert 2 g of phenol into 2, 4, 6-tribromo phenol?
A) 4.00
B) 6.00
C) 10.22
D) 20.44
Explanation
(c)
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Molecular weight of phenol$= 12 \times 6 + 1 \times 6 + 16 = 94$
Molecular weight. Of $Br_{2} = 3 \times 160 = 480$
$\because$ 94 g of phenol requires=480g of $Br_{2}$
$\therefore$ 2 g phenol requires=$\frac{480}{94} \times 2 = 10.22$ g
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.