Q. An organic compound ‘X ’ on treatment with pyridinium chloro chromate in dichloromethane gives compound ‘Y ’. Compound ‘Y’,reacts with $I_{2}$ and alkali to form triiodomethane. The compound ‘X ’ is
A) $C_{2}H_{5}OH$
B) $CH_{3}CHO$
C) $CH_{3}COCH_{3}$
D) $CH_{3}COOH$
Explanation
(a)
$C_{2}H_{5}OH + \lbrack O\rbrack\underset{in\ {CH}_{2}{Cl}_{2}}{\overset{\ \ \ \ \ \ PCC\ \ \ \ \ \ \ \ }{\rightarrow}}CH_{3}CHO$
(X) (Y)
$CH_{3}CHO + 4NaOH + 3I_{2} \rightarrow CHI_{3} + HCOONa + 3H_{2}O + 3NaI$
(Y)
(yellow ppt
tri-iodomethane)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.