Q. Tert-butyl methyl ether on heating with anhydrous HI in ether gives
A) $CH_{3}OH + \left( CH_{3} \right)_{3}CI$
B) $CH_{3}I + \left( CH_{3} \right)_{3}COH$
C) $CH_{3}I + \left( CH_{3} \right)_{3}Cl$
D) None of the above
Explanation
(b)
Here, ether is the solvent. Being less polar, it favours $S_{N}2$ reaction and the nucleophile $I^{-}$attacks the $1^{0}$ carbon of $CH_{3}$.
[image:11_image310.emf]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.