Q. When compound X is oxidised by acidified potassium dichromate, compound Y is formed. Compound Y on reduction with $LiAlH_{4}$ gives X. X and Y respectively are
A) $C_{2}H_{5}OH,\ CH_{3}COOH$
B) $CH_{3}COCH_{3},\ CH_{3}COOH$
C) $C_{2}H_{5}OH,\ CH_{3}COCH_{3}$
D) $CH_{3}CHO,\ CH_{3}COCH_{3}$
Explanation
(a)
When ethyl alcohol is oxidised by acidified potassium dichromate, $CH_{3}COOH$(Y) is obtained as
$3C_{2}H_{5}OH + 2K_{2}Cr_{2}O_{7} + 8H_{2}SO_{4} \rightarrow 3CH_{3}COOH + 2Cr_{2}\left( SO_{4} \right)_{3} + 2K_{2}SO_{4} + 11H_{2}O$
X Y
Carboxylic acid undergoes reduction with $LiAlH_{4}$ to give primary alcohol as
$.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.