(b)
$CH_{3}OH\ and\ C_{2}H_{5}OH$ can be differentiated by using $Na_{2}CO_{3}$ and $I_{2}.\ C_{2}H_{5}OH$ gives yellow precipitate of $CHI_{3}$ whereas $CH_{3}OH$ does not react with it.
$C_{2}H_{5}OH + 4I_{2} + Na_{2}CO_{3} \rightarrow CHI_{3} + 5NaI + HCOONa + 3CO_{2} + H_{2}O$
(iodoform
Yellow ppt)